Post by Masahiro Sakurai on Feb 10, 2022 17:52:22 GMT 10
In Fire Emblem: Three Houses, you play as a professor, tutoring your students and fighting alongside them in battle to improve their stats. Eventually, students can sit certification exams. Pass, and they can change into a better class. You'll be emulating this by taking a test on your mathematical skills, but in a different way to what you remember from school!
In this challenge, you'll have 15 minutes to solve 10 Mystery Sign puzzles. Each puzzle will consist of five "mathematical" equations that all feature one mystery sign. This mystery sign will be represented by a question mark. The first three equations will be evaluated for you; to solve each puzzle you will need to use the three given equations to figure out what the mystery sign is, and then use it to solve the fourth equation. For example:
Puzzle A:
4 ? 3 = 7
5 ? 10 = 15
7 ? 3 = 10
9 ? 9 = ?
The mystery sign in this case would be the first number plus the second number.
The ten mystery sign puzzles will be grouped according to difficulty, with four easy puzzles, three medium, and three hard. The easy puzzles will tend to have more obvious solutions that rely on pure arithmetic. The medium puzzles will introduce some more lateral thinking, while the hard puzzles will combine that with some tougher maths.
To answer each puzzle, simply post the phrase "Puzzle X:" followed by your answer in your challenge thread. Make sure it is very clear to us what puzzle your answer is for; if we're in any way unsure when tallying your answer, we'll consider it incorrect. There is no need to answer in any particular order, so feel free to move between puzzles if you get stuck. You may also change your answer for a puzzle as many times as you like before the time limit passes. Of course, we will only consider the most recent answer for each puzzle when tallying.
The player(s) with the highest score(s) will survive the arena and, if applicable, select a tribe to return to. The loser will be eliminated from the game. In the event of a tie, the winner will be the player who reached the tied score in the shortest time.